A.R1 will forward the packet out all interfaces.
B.R1 will drop this packet because this it is not a valid IP address.
C.As R1 forwards the frame containing this packet, Sw-A will add 192.168.1.255 to its MAC table.
D.R1 will encapsulate the packet in a frame with a destination MAC address of FF-FF-FF-FF-FF-FF
E.As R1 forwards the frame containing this packet, Sw-A will forward it to the device assigned the IP address of 192.168.1.255.

A.Drop the data.
B.Send the data frames to the default gateway.
C.Create an ARP request to get a MAC address for the receiving host.
D.Send a TCP SYN and wait for the SYN ACK with the IP address of the receiving host.

A.10.0.0.0/22 is subnetted，1 subnets D  10.4.0.0[90/20514560] via 10.2.0.2，6w0d，serial0/1
B.10.0.0.0/28 is subnetted，1 subnets D 10.2.0.0[90/20514560] via 10.2.0.2，6w0d，serial0/1
C.10.0.0.0/22 is subnetted，1 subnets D 10.0.0.0[90/20514560] via 10.2.0.2，6w0d，serial0/1
D.10.0.0.0/30 is subnetted，1 subnets D 10.2.2.0[90/20514560] via 10.2.0.2，6w0d，serial0/1
E.10.0.0.0/28 is subnetted，1 subnets D 10.4.4.0[90/20514560] via 10.2.0.2，6w0d，serial0/1
F.10.0.0.0/30 is subnetted，1 subnets D 10.4.4.4[90/20514560] via 10.2.0.2，6w0d，serial0/1

A.mismatched TKIP encryption
B.null SSID
C.cordless phones
D.mismatched SSID
E.metal file cabinets
F.antenna type or direction

A.Send periodic updates regardless of topology changes.
B.Send entire routing table to all routers in the routing domain.
C.Use the shortest-path algorithm to the determine best path.
D.Update the routing table based on updates from their neighbors.
E.Maintain the topology of the entire network in its database.